2. Questions Bank
  3. JEE Main & Advanced
  4. Mathematics
  5. Conic Sections

JEE Main & Advanced Mathematics Conic Sections Question Bank Parabola

  • question_answer
     Vertex of the parabola \[{{y}^{2}}+2y+x=0\] lies in the quadrant [MP PET 1989]

    A)            First                                           

    B)            Second                                      

    C)            Third                                          

    D)            Fourth

    Correct Answer: D

    Solution :

               Given parabola can be written as \[{{(y+1)}^{2}}=-(x-1)\].                    Hence vertex is (1, ?1), which lies in IV quadrant.


You need to login to perform this action.
You will be redirected in 3 sec spinner