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JEE Main & Advanced Mathematics Conic Sections Question Bank Parabola

  • question_answer
    The equation of the parabola with (?3, 0) as focus and \[x+5=0\] as directirx, is   [RPET 1985, 86, 89; MP PET 1991]

    A)            \[{{x}^{2}}=4(y+4)\]                  

    B)            \[{{x}^{2}}=4(y-4)\]

    C)            \[{{y}^{2}}=4(x+4)\]                  

    D)            \[{{y}^{2}}=4(x-4)\]

    Correct Answer: C

    Solution :

               Directrix \[=x+5=0\]            Focus is (?3, 0) Þ \[2a=(-5+3)=2\]Þ \[a=1\]            Vertex is \[\left( \frac{-3+(-5)}{2},\,0 \right)=(-4,\,0)\]            Therefore, equation is \[{{(y-0)}^{2}}=4(x+4)\].


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