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JEE Main & Advanced Mathematics Conic Sections Question Bank Parabola

  • question_answer
    The equation of the parabola whose vertex and focus lies on the x-axis at distance a and a? from the origin, is  [RPET 2000]

    A)                             

    B)            \[{{y}^{2}}=4(a'-a)(x+a)\]

    C)            \[{{y}^{2}}=4(a'+a)(x-a)\]         

    D)            \[{{y}^{2}}=4(a'+a)(x+a)\]

    Correct Answer: A

    Solution :

               Equation will be of the form\[{{y}^{2}}=4A(x-a)\], where \[A=({a}'-a)\] or \[{{y}^{2}}=4({a}'-a)(x-a)\].


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