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JEE Main & Advanced Mathematics Conic Sections Question Bank Parabola

  • question_answer
    Vertex of the parabola \[{{x}^{2}}+4x+2y-7=0\] is [MP PET 1990]

    A)            (?2, 11/2)                                  

    B)            (?2, 2)

    C)            (?2, 11)                                     

    D)            (2, 11)

    Correct Answer: A

    Solution :

               \[{{(x+2)}^{2}}=-2y+7+4\]Þ \[{{(x+2)}^{2}}=-2\left( y-\frac{11}{2} \right)\]            Hence vertex is \[\left( -2,\frac{11}{2} \right)\].


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