A) \[3y=2\]
B) \[x+3y=3\]
C) \[2x=3\]
D) \[y=3\]
Correct Answer: A
Solution :
Since \[9{{y}^{2}}-16x-12y-57=0\] Þ \[{{\left( y-\frac{2}{3} \right)}^{2}}=\frac{16}{9}\left( x+\frac{61}{16} \right)\] Put \[y-\frac{2}{3}=Y\]and \[x+\frac{61}{16}=X\]Þ \[{{Y}^{2}}=4\left( \frac{4}{9} \right)\,X\] Axis of this parabola is \[Y=0\]Þ \[y-\frac{2}{3}=0\]Þ\[3y=2\].You need to login to perform this action.
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