A) \[\left( \frac{3}{2},\ \frac{-1}{2} \right)\]
B) \[\left( 1,\ \frac{-1}{2} \right)\]
C) (1, 0)
D) (0, 1)
Correct Answer: C
Solution :
The parabola is \[{{x}^{2}}-2x=2y\] or \[{{x}^{2}}-2x+1=2y+1\]Þ \[{{(x-1)}^{2}}=2\left( y+\frac{1}{2} \right)\] Here \[4a=2\Rightarrow a=\frac{1}{2}\] Now focus is \[\left( x-1=0,\,y+\frac{1}{2}=\frac{1}{2} \right)\,\,i.e.,\,(1,\,0)\].You need to login to perform this action.
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