A) 36
B) 9
C) 6
D) 4
Correct Answer: D
Solution :
\[9{{x}^{2}}-6x+19=-36y\] Þ \[{{(3x-1)}^{2}}=-36y-18=-36\left( y+\frac{1}{2} \right)\] Þ \[9{{\left( x-\frac{1}{3} \right)}^{2}}=-36\left( y+\frac{1}{2} \right)\] Hence length of latus rectum is 4.
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