A) \[{{(x+a)}^{2}}=\frac{l}{2}(2y-2b)\]
B) \[{{(x-a)}^{2}}=\frac{l}{2}(2y-2b)\]
C) \[{{(x+a)}^{2}}=\frac{l}{4}(2y-2b)\]
D) \[{{(x-a)}^{2}}=\frac{l}{8}(2y-2b)\]
Correct Answer: B
Solution :
The equation of the parabola referred to its vertex as the origin is \[{{X}^{2}}=lY,\]where \[x=X+a,\,\,y=Y+b\]. Therefore the equation of the parabola referred to the point (a,b) as the vertex is \[{{(x-a)}^{2}}=l(y-b)\] or \[{{(x-a)}^{2}}=\frac{l}{2}(2y-2b)\].
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