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JEE Main & Advanced Mathematics Conic Sections Question Bank Parabola

  • question_answer
    The points of intersection of the curves whose parametric equations are \[x={{t}^{2}}+1,\ y=2t\] and \[x=2s,\ y=\frac{2}{s}\] is given by

    A)            \[(1,\ -3)\]                                

    B)            (2, 2)

    C)            (?2, 4)                                       

    D)            (1, 2)

    Correct Answer: B

    Solution :

               Eliminating t from \[x={{t}^{2}}+1,\,\,y=2t,\] we obtain \[{{y}^{2}}=4x-4\]            Similarly eliminating s from \[x=2s,\,y=\frac{2}{s},\]we get \[xy=4.\]            Hence point of intersection is (2, 2).


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