A) \[y\pm 2x=0\]
B) \[2y\pm x=0\]
C) \[x\pm 2y=0\]
D) \[2x\pm y=0\]
Correct Answer: C
Solution :
\[{{y}^{2}}=6.24\]Þ \[y=\pm 12\] Therefore, the points are \[(24,\,12),\,(24,-12)\] Hence lines are \[y=\pm \frac{12}{24}x\Rightarrow 2y=\pm x\].
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