A) 3
B) 6
C) \[\frac{1}{2}\]
D) 9
Correct Answer: C
Solution :
\[4{{y}^{2}}+2x-20y+17=0\] \[2{{\left( y-\frac{5}{2} \right)}^{2}}=-(x-4)\]Þ\[4a=\frac{1}{2}\].
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