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JEE Main & Advanced Mathematics Conic Sections Question Bank Parabola

  • question_answer
    The vertex of the parabola \[{{x}^{2}}+8x+12y+4=0\] is [DCE 1999]

    A) (-4, 1)                                       

    B) (4, -1)

    C) (-4, -1)                                     

    D) (4, 1)

    Correct Answer: A

    Solution :

    Given parabola is  \[{{x}^{2}}+8x+12y+4=0\]            It can be written as \[{{(x+4)}^{2}}=-12y+12\]           \[\Rightarrow \,{{(x+4)}^{2}}=-12(y-1)\], \ vertex is \[(-\,4,\,1).\]


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