A) (-4, 1)
B) (4, -1)
C) (-4, -1)
D) (4, 1)
Correct Answer: A
Solution :
Given parabola is \[{{x}^{2}}+8x+12y+4=0\] It can be written as \[{{(x+4)}^{2}}=-12y+12\] \[\Rightarrow \,{{(x+4)}^{2}}=-12(y-1)\], \ vertex is \[(-\,4,\,1).\]You need to login to perform this action.
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