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JEE Main & Advanced Mathematics Conic Sections Question Bank Parabola

  • question_answer
    The vertex of parabola \[{{(y-2)}^{2}}=16(x-1)\] is  [Karnataka CET 2001]

    A)            (2, 1)                                         

    B)            (1, ?2)

    C)            (?1, 2)                                       

    D)            (1, 2)

    Correct Answer: D

    Solution :

               We know that the standard equation of parabola is \[{{(y-k)}^{2}}=4a(x-h).\] Comparing the given equation with the standard equation, we get \[h=1,\,k=2\] and \[4a=16\] or \[a=4.\] Therefore vertex of the parabola\[\equiv \,(h,\,k)\equiv (1,\,2)\].


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