A) \[{{(4x+3y)}^{2}}-256x-142y+849=0\]
B) \[{{(4x-3y)}^{2}}-256x-142y+849=0\]
C) \[{{(3x+4y)}^{2}}-142x-256y+849=0\]
D) \[{{(3x-4y)}^{2}}-256x-142y+849=0\]
Correct Answer: A
Solution :
\[P{{M}^{2}}=P{{S}^{2}}\] \[\Rightarrow \] \[{{(x-5)}^{2}}+{{(y-3)}^{2}}={{\left( \frac{3x-4y+1}{\sqrt{9+16}} \right)}^{2}}\]You need to login to perform this action.
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