A) \[x=\frac{3}{4}\]
B) \[y=\frac{3}{4}\]
C) \[x=-\frac{1}{2}\]
D) \[x-3y=5\]
Correct Answer: A
Solution :
Given equation of parabola is \[2{{x}^{2}}+5y-3x+4=0\] \[\Rightarrow \] \[{{x}^{2}}-\frac{3}{2}x=-\frac{5}{2}y-2\]\[\Rightarrow \] \[{{\left( x-\frac{3}{4} \right)}^{2}}=-\frac{5}{2}y-\frac{23}{16}\] \[\therefore \] Equation of axis is,\[x-\frac{3}{4}=0\] \[\Rightarrow \] \[x=\frac{3}{4}\]
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