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JEE Main & Advanced Mathematics Conic Sections Question Bank Parabola

  • question_answer
    The equation of the tangent to the parabola \[y={{x}^{2}}-x\] at the point where \[x=1\], is            [MP PET 1992]

    A)            \[y=-x-1\]                                  

    B)            \[y=-x+1\]

    C)            \[y=x+1\]                                   

    D)            \[y=x-1\]

    Correct Answer: D

    Solution :

               Point (1, 0) Þ \[{{\left( \frac{dy}{dx} \right)}_{(1,\,0)}}=2-1=1\]                    Hence the tangent is\[y-0=x-1\].


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