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JEE Main & Advanced Mathematics Conic Sections Question Bank Parabola

  • question_answer
    If the parabola \[{{y}^{2}}=4ax\] passes through the point (1, ?2), then the tangent at this point is                 [MP PET 1998]

    A)            \[x+y-1=0\]                               

    B)            \[x-y-1=0\]

    C)            \[x+y+1=0\]                               

    D)            \[x-y+1=0\]

    Correct Answer: C

    Solution :

               \[\because \] Parabola passes through the point (1,?2), then \[4=4a\Rightarrow a=1\]            Formula for tangent, \[y{{y}_{1}}=2a(x+{{x}_{1}})\]Þ \[-2y=2(x+1)\]            Required tangent is, \[x+y+1=0\].


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