A) \[x{{u}_{x}}=y{{y}_{y}}\]
B) \[y{{u}_{x}}=x{{u}_{y}}\]
C) \[y{{u}_{x}}+x{{u}_{y}}=0\]
D) \[{{x}^{2}}{{u}_{y}}+{{y}^{2}}{{u}_{x}}=0\]
Correct Answer: B
Solution :
\[{{u}_{x}}={{e}^{-{{x}^{2}}-{{y}^{2}}}}(-2x)=-2ux\], \[{{u}_{y}}={{e}^{-{{x}^{2}}-{{y}^{2}}}}(-2y)=-2uy\] \[y{{u}_{x}}=x{{u}_{y}}\].
You need to login to perform this action.
You will be redirected in
3 sec
