A) \[{{C}_{2}}{{H}_{12}}{{O}_{6}}\]
B) \[{{C}_{5}}{{H}_{10}}{{O}_{5}}\]
C) \[{{C}_{4}}{{H}_{8}}{{O}_{8}}\]
D) \[{{C}_{3}}{{H}_{6}}{{O}_{3}}\]
Correct Answer: A
Solution :
\[\because \] 0.0835 mole of compound contains 1gm of hydrogen \[\therefore \] 1gm mole of compound contain = \[\frac{1}{0.0835}=11.97\] =12gm of hydrogen. 12 gm of \[{{H}_{2}}\] is present in \[{{C}_{2}}{{H}_{12}}{{O}_{6}}\]
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