A) 33.33
B) 32.14
C) 31.1
D) 30
Correct Answer: B
Solution :
[b] Let total number of men \[=x\] and total number of women \[=y\] \[\therefore \] Number of married men \[=\frac{45x}{100}\] and number of married women\[=\frac{25y}{100}\] According to the question, \[\frac{45x}{100}=\frac{25y}{100}\] \[\Rightarrow \] \[y=\frac{9x}{5}\] (i) \[\therefore \] Total number of married adults \[=\frac{45x}{100}+\frac{25y}{100}\] \[=\frac{9x}{20}+\frac{9x}{20}\] [Using Eq. (i)] \[=\frac{9x}{10}\] \[\therefore \] Required percentage \[=\frac{\frac{9x}{10}}{\frac{14x}{5}}\times 100\] \[=32.14%\] |
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