A) 40
B) 32
C) 22
D) 8
Correct Answer: D
Solution :
[d] Let A = Set of students who play football and B = Set of students who play cricket. Then,\[n\,\,(A)=40,\]\[n\,\,(B)=50\] and \[n\,(A\cup B)=(100-18)=82\] \[\Rightarrow \] \[n\,\,(A\cup B)=n\,\,(A)+n\,\,(B)-n\,\,(A\cap B)\] \[n\,\,(A\cap B)=n\,\,(A)+n\,\,(B)-n\,\,(A\cup B)\] \[=(40+50-82)=8\] \[\therefore \] Percentage of the students who play both \[=8%\] |
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