A) 32 kg
B) 40 kg
C) 52 kg
D) 80 kg
Correct Answer: B
Solution :
| [b] Quantity of water in 100 kg of fresh fruits \[=\left( \frac{68}{100}\times 100 \right)kg\] \[=68\,\,kg\] Quantity of pulp in it \[=(100-68)\,kg\] Let the dry fruit be x kg. Water in it \[=\left( \frac{20}{100\times x} \right)kg=\frac{x}{5}kg\] Quantity of pulp in it \[=\left( x-\frac{x}{5} \right)kg\] \[=\frac{4x}{5}kg\] \[\therefore \] \[\frac{4x}{5}=32\] \[\Rightarrow \] \[x=\frac{32\times 5}{4}=40\,kg\] |
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