A) 10 m/s
B) 5 m/s
C) 2.5 m/s
D) \[5\sqrt{2}\,m/s\]
Correct Answer: D
Solution :
Initial momentum = \[\vec{P}=mv\hat{i}+mv\hat{j}\] \[|\vec{P}|=\sqrt{2}mv\] Final momentum = \[2m\times V\] By the law of conservation of momentum \[2m\times V=\sqrt{2}\ mv\]Þ \[V=\frac{v}{\sqrt{2}}\] In the problem \[v=10m/s\] (given) \ \[V=\frac{10}{\sqrt{2}}=5\sqrt{2}\ m/s\]
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