A) 600 Joule
B) 800 Joule
C) 1000 Joule
D) 1200 Joule
Correct Answer: B
Solution :
\[{{m}_{1}}{{v}_{1}}+{{m}_{2}}{{v}_{2}}=({{m}_{1}}+{{m}_{2}}){{v}_{\text{sys}\text{.}}}\] \[20\times 10+5\times 0=(20+5)\ {{v}_{\text{sys}\text{.}}}\] Þ \[{{v}_{\text{sys}\text{.}}}=8\,m/s\] K.E. of composite mass \[=\frac{1}{2}(20+5)\times {{(8)}^{2}}=800\,J\]
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