JEE Main & Advanced Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति Question Bank Perfectly Inelastic Collision

  • question_answer
    A neutron having mass of \[1.67\times {{10}^{-27}}kg\] and moving at \[{{10}^{8}}m/s\] collides with a deutron at rest and sticks to it. If the mass of the deutron is\[3.34\times {{10}^{-27}}kg\]then the speed of the combination is                    [CBSE PMT 2000]

    A)             \[2.56\times {{10}^{3}}m/s\]

    B)               \[2.98\times {{10}^{5}}m/s\]

    C)             \[3.33\times {{10}^{7}}m/s\]

    D)               \[5.01\times {{10}^{9}}m/s\]

    Correct Answer: C

    Solution :

                    According to law of conservation of momentum. Momentum of neutron = Momentum of combination Þ\[1.67\times {{10}^{-27}}\times {{10}^{8}}=(1.67\times {{10}^{-27}}+3.34\times {{10}^{-27}})\ v\] \\[v=3.33\times {{10}^{7}}\,m/s\]


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