A) 440 J
B) 392 J
C) 48 J
D) 144 J
Correct Answer: C
Solution :
Loss in kinetic energy \[=\frac{1}{2}\frac{{{m}_{1}}{{m}_{2}}{{({{u}_{1}}-{{u}_{2}})}^{2}}}{{{m}_{1}}+{{m}_{2}}}=\frac{1}{2}\left( \frac{40\times 60}{40+60} \right){{(4-2)}^{2}}\]\[=48\,Joule\]
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