A) Zero
B) 288 J
C) 172.8 J
D) 144 J
Correct Answer: C
Solution :
Loss in K.E. = \[\frac{{{m}_{1}}{{m}_{2}}}{2({{m}_{1}}+{{m}_{2}})}{{\left( {{u}_{1}}-{{u}_{2}} \right)}^{2}}\] = \[\frac{4\times 6}{2\times 10}\times {{(12-0)}^{2}}\]= 172.8 J
You need to login to perform this action.
You will be redirected in
3 sec
