A) Zero
B) 5 cm
C) 2.5 cm
D) 1.25 cm
Correct Answer: D
Solution :
Initially mass 10 gm moves with velocity 100 cm/s \ Initial momentum = 10 × 100 = \[1000\frac{gm\times m}{\sec }\] After collision system moves with velocity \[{{v}_{\text{sys}\text{.}}}\] then Final momentum = \[(10+10)\times {{v}_{\text{sys}\text{.}}}\] By applying the conservation of momentum 10000 = \[20\times {{v}_{\text{sys}\text{.}}}\]Þ \[{{v}_{\text{sys}\text{.}}}==50\ cm/s\] If system rises upto height h then \[h=\frac{v_{\text{sys}\text{.}}^{\text{2}}}{2g}=\frac{50\times 50}{2\times 1000}=\frac{2.5}{2}=1.25\ cm\]
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