A) \[204\text{ }{{m}^{2}}\]
B) \[408\text{ }{{\text{m}}^{2}}\]
C) \[816\,{{m}^{2}}\]
D) \[402\,{{m}^{2}}\]
Correct Answer: B
Solution :
Area of parallelogram ABCD = Area of \[\Delta ADC\]+ Area of \[\Delta ABC\] \[=\frac{1}{2}\times 34\times 12+\frac{1}{2}\times 34\times 12\] \[=204+204=408\text{ }{{m}^{2}}\]You need to login to perform this action.
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