A)
X
Y
Z
40
80
176
B)
X
Y
Z
40
88
136
C)
X
Y
Z
40
80
120
D)
X
Y
Z
80
100
120
Correct Answer: B
Solution :
Let the given ratio of atomic weights of X, Y, Z be 5x, 11 x, 17x respectively. Sum of extreme elements\[(5x+17x)=176\](given). \[22x=176,x=\frac{176}{22}=8\] \[\therefore \] At wt. of \[X=5\times 8=40,Y=11\times 8=88,\] \[\text{Z}=\text{17}\times \text{8}=\text{136}\].You need to login to perform this action.
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