Element X | \[I{{E}_{1}}\] | \[I{{E}_{2}}\] | \[I{{E}_{3}}\] | \[I{{E}_{4}}\] |
496 kJ/mol | 4564 kJ/mol | 6918 kJ/mol | 9542 kJ/mol |
A) \[XS{{O}_{4}}\] and \[XC{{l}_{2}}\]
B) \[X{{(S{{O}_{4}})}_{2}}\] and \[{{X}_{2}}Cl\]
C) \[{{X}_{2}}S{{O}_{4}}\] and\[XCl\]
D) \[XS{{O}_{4}}\] and \[{{X}_{2}}Cl\]
Correct Answer: C
Solution :
There is a big difference in \[I{{E}_{1}}\]and \[I{{E}_{2}}\] which means the element can form only unipositive ion i.e., \[{{X}^{+}}\] easily. \[\therefore \] The formula of sulphate of X is \[{{X}_{2}}S{{O}_{4}}\] and that of chloride of X is XCI.You need to login to perform this action.
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