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10th Class Science Periodic Classification of Elements Question Bank Periodic Classification of Elements

  • question_answer
    A brief information about the element X is given below :
    Element X \[I{{E}_{1}}\] \[I{{E}_{2}}\] \[I{{E}_{3}}\] \[I{{E}_{4}}\]
      496 kJ/mol 4564 kJ/mol 6918 kJ/mol 9542 kJ/mol
    The formulae of the sulphate and chloride of element X are respectively

    A) \[XS{{O}_{4}}\] and \[XC{{l}_{2}}\]

    B) \[X{{(S{{O}_{4}})}_{2}}\] and \[{{X}_{2}}Cl\]

    C) \[{{X}_{2}}S{{O}_{4}}\] and\[XCl\]

    D) \[XS{{O}_{4}}\] and \[{{X}_{2}}Cl\]

    Correct Answer: C

    Solution :

    There is a big difference in \[I{{E}_{1}}\]and \[I{{E}_{2}}\] which means the element can form only unipositive ion i.e., \[{{X}^{+}}\] easily. \[\therefore \] The formula of sulphate of X is \[{{X}_{2}}S{{O}_{4}}\] and that of chloride of X is XCI.


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