A) 1
B) 4
C) 8
D) 2
Correct Answer: D
Solution :
\[\sin \,\left( \frac{x}{n} \right)=\sin \,\left( 2\pi +\frac{x}{n} \right)\] = \[\sin \left( \frac{1}{n}(2n\pi +x) \right)\] Þ Period of the function sin \[\left( \frac{x}{n} \right)\]is \[2n\pi \]. Þ \[2n\pi =4\pi \]\[\Rightarrow n=2\].You need to login to perform this action.
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