A) 90
B) 80
C) 88
D) 82
E) None of these
Correct Answer: A
Solution :
Explanation Option [a] is correct. When L and T are fixed as first and last letters of the word, then we have only 6 letters to be arranged. Hence required number of permutations \[=\frac{6!}{2!\,\times 2!\,\times 2!}=90\]
You need to login to perform this action.
You will be redirected in
3 sec
