A) 0.2 m
B) 0.4 m
C) 0.8 m
D) 1.6 m
Correct Answer: C
Solution :
According to the problem \[\frac{{{I}_{A}}}{{{x}^{2}}}=4\frac{{{I}_{B}}}{{{(1.2-x)}^{2}}}\] \[\Rightarrow \frac{1}{{{x}^{2}}}=\frac{4}{{{(1.2-x)}^{2}}}\] \[\Rightarrow \frac{1}{x}=\frac{2}{1.2-x}\]\[\Rightarrow x=0.4\,m\] and \[1.2-x=0.8\,m\].You need to login to perform this action.
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