A) 80 W
B) 176 W
C) 88 W
D) 36 W
Correct Answer: C
Solution :
Efficiency of light source \[\eta =\frac{\varphi }{p}\] ..... (i) and \[L=\frac{\varphi }{4\pi }\] ..... (ii) From equation (i) and (ii) \[\Rightarrow p=\frac{4\pi L}{\eta }=\frac{4\pi \times 35}{5}\approx 88\,W\].
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