A) 1 : 1
B) 1 : 2
C) 1 : 3
D) 1 : 4
Correct Answer: B
Solution :
\[E={{W}_{0}}+{{K}_{\max }}\] ?..(i) \[\Rightarrow hf={{W}_{A}}+{{K}_{A}}\] ?..(ii) and \[2hf={{W}_{B}}+{{K}_{B}}=2{{W}_{A}}+{{K}_{B}}\] \[\left( \because \,\,\frac{{{W}_{A}}}{{{W}_{B}}}=\frac{1}{2} \right)\] Dividing equation (i) by (ii) \[\frac{1}{2}=\frac{{{W}_{A}}+{{K}_{A}}}{2{{W}_{A}}+{{K}_{B}}}\Rightarrow \frac{{{K}_{A}}}{{{K}_{B}}}=\frac{1}{2}\]
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