A) \[4\times {{10}^{10}}Hz\]
B) \[4\times {{10}^{11}}Hz\]
C) \[4\times {{10}^{14}}Hz\]
D) \[4\times {{10}^{-10}}Hz\]
Correct Answer: C
Solution :
Minimum frequency : \[{{W}_{0}}=h{{\nu }_{0}}\] Þ \[{{\nu }_{0}}=\frac{{{W}_{0}}}{h}=\frac{1.65\times 1.6\times {{10}^{-19}}}{6.6\times {{10}^{-34}}}=4\times {{10}^{14}}Hz\]
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