2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Photo Electric Effect, X- Rays & Matter Waves

JEE Main & Advanced Physics Photo Electric Effect, X- Rays & Matter Waves Question Bank Photon and Photoelectric Effect

  • question_answer
    Light of two different frequencies whose photons have energies \[1eV\] and \[2.5eV\] respectively, successively illuminates a metal of work function \[0.5eV\]. The ratio of maximum kinetic energy of the emitted electron will be [AIEEE 2002]

    A)            1 : 5                                          

    B)            1 : 4

    C)            1 : 2                                          

    D)            1 : 1

    Correct Answer: B

    Solution :

                       By using\[E={{W}_{0}}+{{K}_{\max }}\]\[\Rightarrow {{K}_{\max }}=E-{{W}_{0}}\]                    Hence, \[{{K}_{1}}=1-0.5=0.5\]            and \[{{K}_{2}}=2.5-0.5=2\Rightarrow \frac{{{K}_{1}}}{{{K}_{2}}}=\frac{1}{4}\].


You need to login to perform this action.
You will be redirected in 3 sec spinner