A) \[{{10}^{10}}\]
B) \[{{10}^{20}}\]
C) \[{{10}^{30}}\]
D) \[{{10}^{40}}\]
Correct Answer: C
Solution :
\[P=\frac{W}{t}=\frac{nhc}{\lambda t}\Rightarrow {{10}^{3}}=\frac{n\times 6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{198.6\times 1}\] \[\Rightarrow n={{10}^{30}}\].
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