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JEE Main & Advanced Physics Photo Electric Effect, X- Rays & Matter Waves Question Bank Photon and Photoelectric Effect

  • question_answer
    If the energy of a photon corresponding to a wavelength of 6000 Å is \[3.32\times {{10}^{-19}}J\], the photon energy for a wavelength of 4000 Å will be                                                            [DPMT 2004]

    A)            1.4 eV                                      

    B)            4.9 eV

    C)            3.1 eV                                      

    D)            1.6 eV

    Correct Answer: C

    Solution :

                       \[E=\frac{hc\,}{\lambda }\,\Rightarrow \,\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}\,\Rightarrow \,\frac{3.32\times {{10}^{-19}}}{{{E}_{2}}}=\frac{4000}{6000}\]            \[\Rightarrow \,\,{{E}_{2}}=4.98\times {{10}^{-19}}J=3.1\,eV.\]


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