A) 4.8 eV
B) 2.4 eV
C) 1.4 eV
D) 0.8 eV
Correct Answer: C
Solution :
Work function \[{{W}_{0}}=h{{\nu }_{0}}=6.6\times {{10}^{-34}}\times 1.6\times {{10}^{15}}\] \[=1.056\times {{10}^{-18}}J\]\[=6.6\,eV\] From \[E={{W}_{0}}+{{K}_{\max }}\,\Rightarrow \,\,{{K}_{\max }}=E-{{W}_{0}}\]\[=1.4\,eV\]
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