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JEE Main & Advanced Physics Photo Electric Effect, X- Rays & Matter Waves Question Bank Photon and Photoelectric Effect

  • question_answer
    The ratio of the energy of a photon with \[\lambda =150\,nm\] to that with \[\lambda =300\,nm\] is                                         [DCE 2003]

    A)            2    

    B)            1/4

    C)            4    

    D)            1/2

    Correct Answer: A

    Solution :

               \[E=\frac{hc}{\lambda }\Rightarrow \frac{{{E}_{1}}}{{{E}_{2}}}=\frac{300}{150}=\frac{2}{1}\]


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