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JEE Main & Advanced Physics Photo Electric Effect, X- Rays & Matter Waves Question Bank Photon and Photoelectric Effect

  • question_answer
    Energy of a quanta of frequency \[{{10}^{15}}\]Hz and \[h=6.6\times {{10}^{-34}}J\text{-}\sec \] will be                                   [RPMT 1997]

    A)            \[6.6\times {{10}^{-19}}J\]     

    B)            \[6.6\times {{10}^{-12}}J\]

    C)            \[6.6\times {{10}^{-49}}J\]     

    D)            \[6.6\times {{10}^{-41}}J\]

    Correct Answer: A

    Solution :

               \[E=h\nu =6.6\times {{10}^{-34}}\times {{10}^{15}}=6.6\times {{10}^{-19}}J\]


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