A) \[1.24\times {{10}^{15}}Hz\]
B) \[2.4\times {{10}^{20}}Hz\]
C) \[1.24\times {{10}^{18}}Hz\]
D) \[2.4\times {{10}^{23}}Hz\]
Correct Answer: B
Solution :
\[E=h\nu \,\Rightarrow \,\nu =\frac{E}{h}=\frac{1\times {{10}^{6}}\times 1.6\times {{10}^{-19}}}{6.6\times {{10}^{-34}}}\]\[=2.4\times {{10}^{20}}\,Hz\]
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