A) \[2.42\times {{10}^{26}}Hz\]
B) \[2.42\times {{10}^{16}}Hz\]
C) \[2.42\times {{10}^{12}}Hz\]
D) \[2.42\times {{10}^{9}}Hz\]
Correct Answer: B
Solution :
\[E=h\nu \Rightarrow 100\times 1.6\times {{10}^{-19}}=6.6\times {{10}^{-34}}\times \nu \] \[\Rightarrow \nu =2.42\times {{10}^{16}}Hz\].
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