A) \[4.14\times {{10}^{3}}keV\]
B) \[4.14\times {{10}^{2}}eV\]
C) \[4.14\times {{10}^{3}}MeV\]
D) \[4.14\times {{10}^{3}}eV\]
Correct Answer: D
Solution :
\[E(eV)=\frac{h\nu }{e}=\frac{6.0\times {{10}^{-34}}\times {{10}^{12}}\times {{10}^{6}}}{1.6\times {{10}^{-19}}}\]\[=4.14\times {{10}^{3}}eV\].
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