A) \[6.6\times {{10}^{-19}}J\]
B) \[6.6\times {{10}^{-12}}J\]
C) \[6.6\times {{10}^{-49}}J\]
D) \[6.6\times {{10}^{-41}}J\]
Correct Answer: A
Solution :
\[E=h\nu =6.6\times {{10}^{-34}}\times {{10}^{15}}=6.6\times {{10}^{-19}}J\]You need to login to perform this action.
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