A) \[3.2\times {{10}^{-21}}\]
B) \[3.2\times {{10}^{-19}}\]
C) \[3.2\times {{10}^{-17}}\]
D) \[3.2\times {{10}^{-15}}\]
Correct Answer: B
Solution :
\[{{K}_{\max }}(eV)=E\,(eV)-{{W}_{0}}\,(eV)\]\[=6.2-4.2=2\ eV\] \[\therefore \,\,\,\,\,{{K}_{\max }}(Joules)=\]\[2\times 1.6\times {{10}^{-19}}J=3.2\times {{10}^{-19}}J\]
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